Integrand size = 12, antiderivative size = 63 \[ \int \frac {1}{-3+5 \cos (c+d x)} \, dx=-\frac {\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-2 \sin \left (\frac {1}{2} (c+d x)\right )\right )}{4 d}+\frac {\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+2 \sin \left (\frac {1}{2} (c+d x)\right )\right )}{4 d} \]
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Time = 0.03 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {2738, 212} \[ \int \frac {1}{-3+5 \cos (c+d x)} \, dx=\frac {\log \left (2 \sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )}{4 d}-\frac {\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-2 \sin \left (\frac {1}{2} (c+d x)\right )\right )}{4 d} \]
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Rule 212
Rule 2738
Rubi steps \begin{align*} \text {integral}& = \frac {2 \text {Subst}\left (\int \frac {1}{2-8 x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{d} \\ & = -\frac {\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-2 \sin \left (\frac {1}{2} (c+d x)\right )\right )}{4 d}+\frac {\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+2 \sin \left (\frac {1}{2} (c+d x)\right )\right )}{4 d} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.00 \[ \int \frac {1}{-3+5 \cos (c+d x)} \, dx=-\frac {\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-2 \sin \left (\frac {1}{2} (c+d x)\right )\right )}{4 d}+\frac {\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+2 \sin \left (\frac {1}{2} (c+d x)\right )\right )}{4 d} \]
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Time = 0.65 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.59
method | result | size |
parallelrisch | \(\frac {\ln \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )-\ln \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{4 d}\) | \(37\) |
derivativedivides | \(\frac {\frac {\ln \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{4}-\frac {\ln \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{4}}{d}\) | \(38\) |
default | \(\frac {\frac {\ln \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{4}-\frac {\ln \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{4}}{d}\) | \(38\) |
norman | \(-\frac {\ln \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{4 d}+\frac {\ln \left (2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{4 d}\) | \(40\) |
risch | \(-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {3}{5}-\frac {4 i}{5}\right )}{4 d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {3}{5}+\frac {4 i}{5}\right )}{4 d}\) | \(40\) |
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Time = 0.26 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.73 \[ \int \frac {1}{-3+5 \cos (c+d x)} \, dx=\frac {\log \left (-\frac {3}{2} \, \cos \left (d x + c\right ) + 2 \, \sin \left (d x + c\right ) + \frac {5}{2}\right ) - \log \left (-\frac {3}{2} \, \cos \left (d x + c\right ) - 2 \, \sin \left (d x + c\right ) + \frac {5}{2}\right )}{8 \, d} \]
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Time = 0.40 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.70 \[ \int \frac {1}{-3+5 \cos (c+d x)} \, dx=\begin {cases} - \frac {\log {\left (2 \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )} - 1 \right )}}{4 d} + \frac {\log {\left (2 \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )} + 1 \right )}}{4 d} & \text {for}\: d \neq 0 \\\frac {x}{5 \cos {\left (c \right )} - 3} & \text {otherwise} \end {cases} \]
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Time = 0.25 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.79 \[ \int \frac {1}{-3+5 \cos (c+d x)} \, dx=\frac {\log \left (\frac {2 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right ) - \log \left (\frac {2 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{4 \, d} \]
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Time = 0.28 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.60 \[ \int \frac {1}{-3+5 \cos (c+d x)} \, dx=\frac {\log \left ({\left | 2 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - \log \left ({\left | 2 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right )}{4 \, d} \]
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Time = 14.10 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.27 \[ \int \frac {1}{-3+5 \cos (c+d x)} \, dx=\frac {\mathrm {atanh}\left (2\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{2\,d} \]
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